Question

A spring stretches 2.6 cm when a 7 g object is hung from it. The object is replaced with a block of mass 28 g which oscillates in simple harmonic motion. Calculate the period of motion. The acceleration of gravity is 9.8 m/s 2 . Answer in units of s.

Answer 1

period = 0.65 sec

Step-by-step explanation:

from the question we are given the following

extension (x) = 2.6 cm = 0.026 m

mass of object (Mo) = 7 g = 0.007 kg

mass of block (Mb) = 28 g = 0.028 g

acceleration due to gravity (g) = 9.8 m/s^{2}

period = 2π x
`\sqrt{(Mb)/(k)}`

where k is the spring constant of the spring

and k = \frac{Mo x g}{x}

k = \frac{0.007 x 9.8}{0.026}

k = 2.64 N/m

now period = 2π x
`\sqrt{(0.028)/(2.64)}`

period = 0.65 sec