Question

A trapeze artist on a rope is momentarily held to one side by a partner on a platform The rope makes an angle of 26.0 with the vertical. Insuch a condition of static equilibrium, what is the magnitude of the horizontal force being applied by the partner? The weight of the artist is 7.61 10 N

Answer 1

`F_t=371.16N`

Step-by-step explanation:

The weight 7.61x10^2N

The angle 26.0

To determine the magnitude of horizontal force applied

`tan(\alpha)=(F_t)/(F)`

`F_t=F*tan(\alpha)`

`F_t=7.61x10^2N*tan(26.0)`

`F_t=371.16N`