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A trapeze artist on a rope is momentarily held to one side by a partner on a platform The rope makes an angle of 26.0 with the vertical. Insuch a condition of static equilibrium, what is the magnitude
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A trapeze artist on a rope is momentarily held to one side by a partner on a platform The rope makes an angle of 26.0 with the vertical. Insuch a condition of static equilibrium, what is the magnitude of the horizontal force being applied by the partner? The weight of the artist is 7.61 10 N

User Massimiliano Fliri
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1 Answer

2 votes

Answer:


F_t=371.16N

Step-by-step explanation:

The weight 7.61x10^2N

The angle 26.0

To determine the magnitude of horizontal force applied


tan(\alpha)=(F_t)/(F)


F_t=F*tan(\alpha)


F_t=7.61x10^2N*tan(26.0)


F_t=371.16N

User Askolotl
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