Answer:
The slope of AB is -7/4, the slope of BC is 1/7 , the slope of CD is 5/3, and the slope of AD is 2. So, Quadrilateral ABCD is neither a parallelogram nor a trapezoid because neither pair of opposite sides are parallel.
Explanation:
Since, a quadrilateral having,
One pair of parallel opposite sides is Trapezoid,
While, having two pair of parallel opposite sides is parallelogram.
Since, the slope of a line segment having the end points
and
is,
![m=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2020/formulas/mathematics/high-school/pj0y5tg37a7a9ase0auiwe687ez8iaw2vl.png)
Here, the vertices of the quadrilateral ABCD are A(0, −4) , B(−4, 3) , C(3, 4) , and D(6, −1),
Slope of AB =
![(3+4)/(-4-0)=-(7)/(4)](https://img.qammunity.org/2020/formulas/mathematics/high-school/34w083lpc0xsatsox8v7hfd97gxnd2qywv.png)
Slope of BC =
![(4-3)/(3+4)=(1)/(7)](https://img.qammunity.org/2020/formulas/mathematics/high-school/4cavsk9ys5umnn0e45iv3zceypsku9dd8a.png)
Slope of CD =
![(-1-4)/(6-3)=-(5)/(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/jrxmrd0co2cj0yu86cyfqqae6o1medsjy4.png)
Slope of AD =
Hence, Quadrilateral ABCD is neither a parallelogram nor a trapezoid because neither pair of opposite sides are parallel.