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There are 3 blue, 1 white and 4 red identical balls inside a bag. If it is aimed to take two balls out of the bag consecutively, what is the probability to have 1 blue and 1 white ball?

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Final answer:

The probability of selecting 1 blue and 1 white ball out of the bag is 3/28.

Step-by-step explanation:

To find the probability of selecting 1 blue and 1 white ball out of the bag, we need to consider two scenarios: selecting a blue ball first and then a white ball, or selecting a white ball first and then a blue ball.

1. Probability of selecting a blue ball first and then a white ball: (3 blue balls/8 total balls) * (1 white ball/7 remaining balls) = 3/8 * 1/7 = 3/56

2. Probability of selecting a white ball first and then a blue ball: (1 white ball/8 total balls) * (3 blue balls/7 remaining balls) = 1/8 * 3/7 = 3/56

The total probability is the sum of these two scenarios: 3/56 + 3/56 = 6/56 = 3/28.

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