Question

PLEASE HELP!

A solid object is dropped into a pond with a temperature of 20°C. The function f(t)=Ce^(-my)+20 represents the situation, where T is times in minutes, C is a constant in K= 0.0399.

After four minutes the object has a temperature of 35°C what was the initial temperature of the object round your answer to the nearest tenth, and do not include units

Answer 1

The initial temperature of the object was 37.6

Explanation:

we have

`f(t)=Ce^((-kt)) +20`

where

f(t) represent the temperature of the object in degree Celsius

t is the time in minutes

Find the value of the constant C

we have the ordered pair (4,35)

substitute in the equation and solve for C

`35=Ce^((-0.0399*4)) +20\\Ce^((-0.0399*4))=15\\C=15/e^((-0.0399*4))\\C=17.6`

Find the initial value of the object

we know that

The initial temperature is the value of f(t) when the value of t is equal to zero

so

For t=0

`f(0)=(17.6)e^((-k*0)) +20\\f(0)=17.6 +20\\f(0)=37.6`

therefore

The initial temperature of the object was 37.6 (I not include units)