Question

Which of the following is equivalent to log StartFraction one-ninth over k EndFraction?

log one-ninth minus log k
log 1 minus log StartFraction 9 Over k EndFraction
log one-ninth minus k
log one-ninth + log k

Answer 1

Answer: a

Explanation:

Answer 2

The given expression is equal to,

`\log ((1)/(9)) - \log k`

Explanation:

we are to find the expression equivalent to,

`\log (\frac {\frac {1}{9}}{k})`

which is equal to,

`\log ((1)/(9)) - \log k`

Since, we know that,

`\log (\frac {m}{n})`

=
`\log(m) - \log(n)`

where all the terms are defined.