4/5x + 1/2y= 40 what are the x and y intercepts

Question

asked Jun 10, 2020 150k views

1 Answer

Bjeavons · Answer 1 · 2020-06-16T02:38:34+0000

For this case we have the following equation:

$\frac {4} {5} x + \frac {1} {2} y = 40$

We must find the intersections with the x and y axes respectively.

Intersection with the x axis: Making
we have:

$\frac {4} {5} x + \frac {1} {2} (0) = 40\\\frac {4} {5} x = 40$

We multiply by 5 on both sides of the equation:

$4x = 5 * 40\\4x = 200$

Dividing by 4 to both sides of the equation:

$x = \frac {200} {4}\\x = 50$

Thus, the intersection with the x-axis is given by:
(x, y) :( 50,0)

Intersection with the y axis: Making
we have:

$\frac {4} {5} (0) + \frac {1} {2} y = 40\\\frac {1} {2} y = 40$

We multiply by 2 on both sides of the equation:

$y = 2 * 40\\y = 80$

Thus, the intersection with the y-axis is given by:
(x, y) :( 0,80)

Answer:

Intersection with the x axis: (50,0)

Intersection with the y axis: (0,80)