Question

A line passes through (2, 4) and (-2, 2). Find the value of y if (6, y) lies on the line. Not sure how the 3 was brought into the equation per the last answer to my question.

Answer 1

To find the value of y if (6, y) lies on the line passing through (2, 4) and (-2, 2), we first find the equation of the line. The slope is 1/2, and using the point-slope form of a line, we get y - 4 = (1/2)(x - 2). Substituting x = 6, we find y = 6.

Step-by-step explanation:

To find the value of y if (6, y) lies on the line passing through (2, 4) and (-2, 2), we need to find the equation of the line first.

The slope of the line can be found using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the coordinates of two points on the line.

Using the coordinates (2, 4) and (-2, 2), we get: m = (2 - 4) / (-2 - 2) = -2 / -4 = 1/2.

Now, we can use the point-slope form of a line: y - y1 = m(x - x1).

Using the coordinates (2, 4), we get: y - 4 = (1/2)(x - 2).

Simplifying the equation, we get: y - 4 = (1/2)(x - 2).

Substituting x = 6 into the equation, we can solve for y: y - 4 = (1/2)(6 - 2).

Simplifying the equation, we get: y - 4 = (1/2)(4).

Therefore, y = 6.

Answer 2

Well, that is simple. You first must find the slope of the line from the 2 given points by using the slope formula. Which is y2-y1/x2-x1. So 2-4/-2-2 which equals -2/-4 which is 1/2. So the slope is 1/2. Now we can use the slope intercept form which is y=mx+b to find the slope equation. So we plug in one the points, say (2,4) and get y=1/2x+3. So now we plug in (6,y) Since we know x we can find y. y=1/2(6)+3 which gives us y=6. So y is 6.