a. The equation of line k in slope-intercept form is y = -8/3(x) + 2/3.
b. The equation of line j in slope-intercept form is y = 3/8(x) + 27/4.
In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):
![y - y_1 = m(x - x_1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4exoxzl9wyc78rb7vje3c9oxdf7c81fpof.png)
Where:
- x and y represent the data points.
- m represent the slope.
Since transversal k cuts through lines n and m with two same-side interior angles that are supplementary formed, we can logically deduce that both lines are parallel;
71° + 109° = 180°
Also, line k is perpendicular to lines j, m, and n because transversal k bisects line j at a right angle (90 degrees).
Next, we would determine the slope of line m;
![Slope(m)=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ynisv26e9m05vkjzyt8dxagvswkuguybd2.png)
Slope (m) = (2 + 1)/(5 + 3)
Slope (m) = 3/8
Part a.
Since line k is perpendicular to lines n and m, their slopes must be negative reciprocal of each other;
-8/3 × 3/8 = -1
At data point (-2, 6) and a slope of -8/3, an equation for line k can be calculated by using the point-slope form as follows:
y - 6 = -8/3(x + 2)
y = -8/3(x) - 16/3 + 6
y = -8/3(x) + 2/3
Part b.
Since line j is parallel to lines n and m, their slopes must be the same;
3/8 = 3/8
At data point (-2, 6) and a slope of 3/8, an equation for line k can be calculated by using the point-slope form as follows:
y - 6 = 3/8(x + 2)
y = 3/8(x) + 3/4 + 6
y = 3/8(x) + 27/4