Question

Find the magnitude of the magnetic flux through the floor of a house that measures 24 m by 13 m . Assume that the Earth's magnetic field at the location of the house has a horizontal component of 2.6×10−5 T pointing north, and a downward vertical component of 4.7×10−5 T .

Answer 1

14.6610^{-3}Wb

Step-by-step explanation:

Magnetic flux through a surface is

Φ =BAcosθ

here, B is the magnetic field

A= area through which flux is measured

θ= angle measure between field direction and normal to the surface.

horizontal component of the field is parallel to the surface so the angle made by the normal with the field is 90° and thus flux due to horizontal component is 0 since cos 90 is 0.

in vertical component θ= 0°

Φ = BAcos0° = BA

= 4.7×10^{-5}×24×13 = 1466.4×10^{-5}= 0.01466 Wb = 14.6610^{-3}Wb