Answer:

Explanation:
Given : A A sample of 73 packages of blueberries has a variance of 0.30.
i.e. n= 73 and

Confidence level:
⇒Significance level :

Critical values using chi-square distribution:-


99% confidence interval for population variance will be :-

Hence, the 99% confidence interval to estimate the variance of the weights of the packages prepared by the machine:
