Answer:
The maximum acceleration amplitude is 40.28 g.s.
Step-by-step explanation:
Given that,
Full scale suspension = 25 mm
Frequency = 20 Hz
We need to calculate the maximum frequency
Using formula of maximum frequency
![f=(\omega)/(2\pi)](https://img.qammunity.org/2020/formulas/physics/high-school/ljni3my00br5qk5pq3un0qih4e5ubm6fsl.png)
![\omega=f*2\pi](https://img.qammunity.org/2020/formulas/physics/college/gc9zzhwapa66uwo6i9skg12l152qme8ao1.png)
Put the value into the formula
![\omega=20*2\pi](https://img.qammunity.org/2020/formulas/physics/college/nmawrcv0uzgp9bgjgsdihi146sxq496u0x.png)
![\omega=40\pi\ rad/s](https://img.qammunity.org/2020/formulas/physics/college/jn040ui50wtgkfpx6rwzdws55mcxqrartj.png)
We need to calculate the maximum acceleration amplitude
Using restoring force
![F= -kx](https://img.qammunity.org/2020/formulas/physics/college/72jf5u9qoxjqie4b7z9odd4x32g21q3h6a.png)
![ma=-kx](https://img.qammunity.org/2020/formulas/physics/college/te4mn6856ovh9yz5beud34f7ccn8zkbexv.png)
![a=(-kx)/(m)](https://img.qammunity.org/2020/formulas/physics/college/b78nye0vp7hkohxyjal9yzipbc71og713k.png)
![a=-\omega^2 x](https://img.qammunity.org/2020/formulas/physics/college/tft7qaw0l80oy79hj6a69l61z7u3iq72tb.png)
![|a|=\omega^2 x](https://img.qammunity.org/2020/formulas/physics/college/pwnda942isvo9o570crt7xpi7dfzw7ssy1.png)
Using equation of S.H.M
![x=A\sin\omega t](https://img.qammunity.org/2020/formulas/physics/college/1vnfedvho48qvey0gnghbpr1zguroyvy4y.png)
On differentiating
![(dx)/(dt)=A\omega\cos\omega t](https://img.qammunity.org/2020/formulas/physics/college/pxqnhw2tcwmhomtoxwrib6tt9wsk58188j.png)
On differentiating again
![(d^2x)/(dt^2)=-\omega^2A\sin\omega t](https://img.qammunity.org/2020/formulas/physics/college/3h9p500mlrt6bxh5pubf8nlxo1i06kqvel.png)
![a=-\omega^2A\sin\omega t](https://img.qammunity.org/2020/formulas/physics/college/o2om1nb65mks2xprw3yc2gba4lvewacw3n.png)
Maximum acceleration =ω²A
Which is at the maximum amplitude
![a =\omega^2 A](https://img.qammunity.org/2020/formulas/physics/college/316xlagra2es5hyqf01dy53roeaxfddqai.png)
![a=(40\pi)^2*25*10^(-3)](https://img.qammunity.org/2020/formulas/physics/college/lsneud8uby5b3omkhs7swa4qdo2891rzvo.png)
![a=394.78\ m/s^2](https://img.qammunity.org/2020/formulas/physics/college/swt24c4smdsfwd0zmizo4vniy1hph82u1t.png)
![a=(394.78)/(g)](https://img.qammunity.org/2020/formulas/physics/college/lal4jqkqq72yhozntd18x7hy0tv6kvj3le.png)
![a=40.28\ g.s](https://img.qammunity.org/2020/formulas/physics/college/t4ha7oe8ir4omw63q3zdl3dpe42a5kfkai.png)
Hence, The maximum acceleration amplitude is 40.28 g.s.