Question

Write the standard form of the line that passes through the point (-2,4) and is parallel to x-2y=6

Answer 1

x - 2y + 10 = 0

Explanation:

The equation of parallel line differ only by their constant.

Hence, the equation of the line parallel to
`x - 2y - 6 = 0` is nothing but
`x - 2y + c = 0`.

When a point passing through this line is given we can substitute the point in this line and get the value for
`c`.

The line passes through
`(-2, 4)`.

Therefore, we have:
`-2 - 8 + c = 0 \implies c = 10`

Substituting this we get the equation of the parallel line as
`x - 2y + 10 = 0`.