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Write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the given equation.

(-1,3);y = 2x - 8

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For this case we have that by definition, the equation of a line in the slope-intersection form is given by:


y = mx + b

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

We have the following line:


y = 2x-8

The slope is
m_ {1} = 2

By definition, if two lines are parallel then their slopes are equal. Thus, a line parallel to the given line will have a slope
m_ {2} = 2

Therefore, the equation of the parallel line will be of the form:


y = 2x + b

We substitute the given point and find "b":


3 = 2 (-1) + b\\3 = -2 + b\\3 + 2 = b\\b = 5

Finally, the equation is:


y = 2x + 5

Answer:


y = 2x + 5

User Noseratio
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