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What is the slop intercept form of a line that passes threw (4,-4) and (8, -10)

User Jai Pandya
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1 Answer

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For this case we have that by definition, the equation of a line of the slope-intersection form is given by:


y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We have two points through which the line passes, so we can find the slope:


(x_ {1}, y_ {1}) :( 4, -4)\\(x_ {2}, y_ {2}) :( 8, -10)\\m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-10 - (- 4)} {8-4} = \frac {-10+ 4} {4} = \frac {-6} {4} = - \frac {3} {2}

Thus, the equation is of the form:


y = - \frac {3} {2} x + b

We substitute one of the points and find "b":


-4 = - \frac {3} {2} (4) + b\\-4 = - \frac {12} {2} + b\\-4 + 6 = b\\b = 2

Finally, the equation is of the form:


y = - \frac {3} {2} +2

ANswer:


y = - \frac {3} {2} +2

User Ericb
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