1 Answer

Greg Dougherty · Answer 1 · 2020-05-17T06:42:07+0000

For this case we have the following system of equations:

$4x + 2y = 18\\x-y = 3$

To solve, we clear "x" from the second equation:

x = 3 + y

We substitute "x" in the first equation:

$4 (3 + y) + 2y = 18\\12 + 4y + 2y = 18\\12 + 6y = 18$

We clear the value of the variable "y":

$6y = 18-12\\6y = 6\\y = \frac {6} {6}\\y = 1$

We look for the value of the variable "x":

$x = 3 + y\\x = 3 + 1\\x = 4$

Thus, the solution of the system is given by:

(x, y) :( 4,1)

Answer:

Option D

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