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Question 3 of 15

2 Points

A skydiver slows down from 54 m/s to 4 m/s by opening his parachute. If this

takes 0.75 seconds, what is the magnitude of the skydiver's acceleration?

O

O

A. 37.5 m/s?

B. 50 m/s

2

)

C. 66.7 m/s?

O

D. 9.8 m/s2

SUBMIT

User MingMan
by
7.8k points

1 Answer

5 votes

Answer:

C.
66.7m/s^(2)

Explanation:

We sholud also talk about medium aceleration


a_(m) =(V_(f)-V_(i))/(t_(f)-t_(i)) = a_(m)=(54-4)/(0.75-0) = 66.7m/s^(2)

NOTE :
a=(v/t)=((m)/(s) )/(s) =((m)/(s) )/((s)/(1) )=(m*1)/(s*s) = (m)/(s^(2) ) that are acceleration units

User Changdeo Jadhav
by
8.3k points
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