Question

Solve the system:

22-4y= 14
3y + 5z =9
A. Or = 1, y=1
B. Or = 1, y=-
C.Or=3, y=2
D.O2 = 5, y=-1

Answer 1

`y=2,\ z=(3)/(5)`

Explanation:

Given the following system of equations:

`\left \{ {{22-4y= 14} \atop {3y + 5z =9}} \right.`

You can follow these steps to solve it using the Substitutiong method:

1. Solve for "y" from the first equation in order to finds its value:

`22-4y= 14\\\\-4y= 14-22\\\\y=(-8)/(-4)\\\\y=2`

2. Substitute the value for "y" into the second equation and solve for "z" in order to find its value. This is:

`3(2) + 5z =9\\\\5z=9-6\\\\z=(3)/(5)`