46.5k views
0 votes
3^2 - 2x + 4 and g(x) = 5x^2 + 6x - 8 find f-g(x)

User Kaadzia
by
8.0k points

1 Answer

2 votes

Answer:

For the given functions f(x) and g(x)
(f-g)(x) = -2x^(2)  - 8x +12

Explanation:

Here, the given function are:


f(x)  = 3x^(2)  - 2x+ 4\\g(x) = 5x^(2)  + 6x -8

Now, simplifying for (f-g)(x) = f(x) - g(x):


f(x) - g(x)  = (3x^(2)  - 2x+ 4) - (5x^(2)  + 6x -8)


= 3x^(2)  - 2x+ 4- 5x^(2)  - 6x +8

Doing operation on LIKE TERMS, we get

f(x) - g(x) =
( 3x^(2)- 5x^(2))   + (-2x - 6x)  +( 4 +8) = -2x^(2)  - 8x + 12

Hence, for the given functions f(x) and g(x)
(f-g)(x) = -2x^(2)  - 8x +12

User Puzik
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories