Explanation:
did you leave something out ?
(5p + 3)(p + 1) = 5p×p + 5p×1 + 3×p + 3×1 =
= 5p² + 5p + 3p + 3 = 5p² + 8p + 3
at no point do we have 5 terms to sum up. but 4 and then finally 3, yes.
but we always have also additions, not only multiplications (products).
so, none of the 2 options is correct.
we could, of course. start with the initial expression, that shows the product of 2 factors and multiply by 1×1
(5p + 3)(p + 1)×1×1
then we have the expression as product of 4 factors.
in the same way we could bump up the sum scenario by adding one or 2 0s : tadah ! sum of 5 terms.
I strongly suspect there is something missing in the problem description.