Answer:
A. The central bright fringe becomes wider.
Step-by-step explanation:
Width of central bright fringe is given by the formula
![a sin\theta = N\lambda](https://img.qammunity.org/2020/formulas/physics/college/3twie9mh1xlfzheudckjv9qq0dtfht0x34.png)
now for position of first minima on both sides of central bright fringe is given as
![\theta = \pm (\lambda)/(a)](https://img.qammunity.org/2020/formulas/physics/high-school/ie6zvbli66jvdm4a3dclyjoq7xqyxirhku.png)
so the angular width of central maximum is given as
![\beta = 2\theta](https://img.qammunity.org/2020/formulas/physics/high-school/rp0yoi3v7u5dd9t6a3ecntknfaw4maw8o6.png)
![\beta = 2(\lambda)/(a)](https://img.qammunity.org/2020/formulas/physics/high-school/cao344lpfqfby1t16j9acue2rr11qxx0kn.png)
now width of maximum is given as
![w = (2L\lambda)/(a)](https://img.qammunity.org/2020/formulas/physics/high-school/8s6rkrjk0wgcrzs09bz8vupwrdcvnp6kns.png)
now we can see that this width is inversely depends on the width of slit
so on decreasing the slit width the central maximum width must have to increase