Unfortunately the very last part of problem 1 is cut off. The slope number is missing. So currently I cannot help with it.
The good news is that I can help with problem 2.
The slope is m = -2 and the point the line goes through is
which is a compact way of saying
and
pair up together.
We'll plug those three values into the point slope equation below. Then we'll solve for y.
![y-y_1 = m(x-x_1)\\\\y-2 = -2(x-4)\\\\y-2 = -2x-2(-4)\\\\y-2 = -2x+8\\\\y = -2x+8+2\\\\y = -2x+10\\\\](https://img.qammunity.org/2023/formulas/mathematics/high-school/i6tsy1ok9sa1v2ykbpm3baue83puqy3usq.png)
The answer to problem 2 is y = -2x+10
This equation is in y = mx+b form
- m = -2 = slope
- b = 10 = y intercept
To find any two points on this line, plug in any x value you want to get a paired y value. Let's say we plugged in x = 0
y = -2x+10
y = -2*0+10
y = 10
This shows x = 0 leading to y = 10. The point (x,y) = (0,10) is on this line.
Through similar calculations, you should find (1,8) is another point on the line. Also, plug in x = 4 and it should lead you to y = 2 as a way to confirm the answer.
Once you have at least two points, you can plot them on the same xy grid. Then draw a straight line through them to complete the graph.