Question

How do you solve for a side in a right triangle that has a hypotenuse of 10, an angle of 35, and the side across from the angle is x?

Answer 1

`\sin \theta = \frac{\textrm{opposite}}{\textrm{hypotenuse}}`

`\sin 35^\circ = (x)/(10)`

`x = 10 \sin 35^\circ`

That's the exact answer; they usually want a calculator approximation at this point,

`x \approx 5.735`