Question

A weightlifter lifts a set of weights a vertical distance of 2 meters. If a constant net force of 350 N is exerted on the weights, what is the amount of work done on the weights? :

350N multiplied by 2m = 700

**if the weightlifter in the previous question takes a total of 2 seconds to life the weights, how much power is performed

Answer 1

ANSWER:700J

Step-by-step explanation:

Okay so first you want to write out your givens:

Newtons=350

Degree=0

Distance/Displacement=2.00

Use the Net work Done by a Constant Net Force: W=FdcosФ

W=(350N)(2.00m): No degree, therefore no need to include in the equation

W=700J

Answer 2

The work done by the weightlifter, W = 700 J

The power of the weightlifter, P = 350 watts

Step-by-step explanation:

A weightlifter lifts a set of weights a vertical distance, s = 2 m

The force exerted to lift the weight, F = 350 N

The work done by the body is defined as the product of the force applied by the body to the displacement it caused.

W = F x s

= 350 N x 2 m

= 700 J

The work done by the weightlifter, W = 700 J

The time taken by the weightlifter to lift the weight, t = 2 s

The power is defined as the rate of body to do work. It is given by the equation,

P = W / t

= 700 J / 2 s

= 350 watts

Hence, the power of the weightlifter, P = 350 watts