Answer: a. 94.86%
b. 2067.06 kW
Explanation: a. Tc = 35 C
Th = 680 C
Thermal Efficiency (η) = 1 - Tc/Th
= 1 - 35/680
= 0.9486
Hence Thermal Efficiency of Plant = 94.86%
b. Qh = 2100 kW
Wp = 75 kW
η = (Wt - Wp) / Qh
Wt = (η * Qh) + Wp = (0.9486 * 2100) + 75 = 2067.06 kW