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In a steam power plant, energy is added by heat transfer at a rate of 2100 kW at 680◦C at the boiler, removed at a rate of 1240 kW at 35◦C at the condenser, and the pump power is 75 kW. Determine: a. thermal efficiency of power plant b. maximum possible turbine power [kW] (assume same energy transfers at boiler and pump)

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Answer: a. 94.86%

b. 2067.06 kW

Explanation: a. Tc = 35 C

Th = 680 C

Thermal Efficiency (η) = 1 - Tc/Th

= 1 - 35/680

= 0.9486

Hence Thermal Efficiency of Plant = 94.86%

b. Qh = 2100 kW

Wp = 75 kW

η = (Wt - Wp) / Qh

Wt = (η * Qh) + Wp = (0.9486 * 2100) + 75 = 2067.06 kW

User Om Prakash
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