Answer: b.) 0.9706
Explanation:
Given : Proportion of the 5,000 payroll vouchers issued since January 1, 2000, have irregularities : p=0.10
Now , using standard normal z-value table , we have
The probability that Pinky's random sample of 200 vouchers will have a sample proportion greater than .06 will be :-
[By using z-value table]
Hence, the probability that Pinky's random sample of 200 vouchers will have a sample proportion greater than .06 is b.) 0.9706.