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Water enters a shower head through a pipe of radius 0.0112 m at 3.25 m/s. What is it’s volume flow rate? (Unit= m^3/s)

2 Answers

6 votes

Answer:

For Acellus the answer is 0.00128

Step-by-step explanation:

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User MaGz
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9 votes

Answer:


1.28 * 10 ^(-3) m^3/s

Step-by-step explanation:

Given that the radius of the pipe, r =0.0112 m

So, the area of the cross-section,
a= \pi (0.0112)^2 = 3.941* 10^(-4) m^2

Speed of water in the pipe, v=3.25 m/s

Volume flow rate =
av= 3.941* 10^(-4) * 3.25 = 1.28* 10 ^(-3) m^3/s

Hence, the volume flow rate is
1.28 * 10 ^(-3) m^3/s

User SitWalkStand
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