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-4(4/3v-4)-3(1/2v-4)

2 Answers

3 votes

assuming you want us to simplify

remember

negative times negative=positive

and

remember the distributive proeprty

a(b+c)=ab+ac

and

-a(b+c)=-ab-ac

oh, and order of operations

so

-4(4/3v-4)-3(1/2v-4)

distribute

-4(-4/3v-4)=-4(-4/3v)-4(-4)=16/3v+16

-3(1/2v-4)=-3(1/2v)-3(-4)=-3/2v+12

so we now gots

16/3v+16-3/2v+12

group like terms

16/3v-3/2v+16+12

combine like terms

first the v terms

16/3v-3/2v=32/6v-9/6v=23/6v

then the constants

16+12=28

so we gets

23/6v+28 is the simlified formassuming you want us to simplify

remember

negative times negative=positive

and

remember the distributive proeprty

a(b+c)=ab+ac

and

-a(b+c)=-ab-ac

oh, and order of operations

so

-4(4/3v-4)-3(1/2v-4)

distribute

-4(-4/3v-4)=-4(-4/3v)-4(-4)=16/3v+16

-3(1/2v-4)=-3(1/2v)-3(-4)=-3/2v+12

so we now gots

16/3v+16-3/2v+12

group like terms

16/3v-3/2v+16+12

combine like terms

first the v terms

16/3v-3/2v=32/6v-9/6v=23/6v

then the constants

16+12=28

so we gets

23/6v+28 is the simlified formassuming you want us to simplify

remember

negative times negative=positive

and

remember the distributive proeprty

a(b+c)=ab+ac

and

-a(b+c)=-ab-ac

oh, and order of operations

so

-4(4/3v-4)-3(1/2v-4)

distribute

-4(-4/3v-4)=-4(-4/3v)-4(-4)=16/3v+16

-3(1/2v-4)=-3(1/2v)-3(-4)=-3/2v+12

so we now gots

16/3v+16-3/2v+12

group like terms

16/3v-3/2v+16+12

combine like terms

first the v terms

16/3v-3/2v=32/6v-9/6v=23/6v

then the constants

16+12=28

so we gets

23/6v+28 is the simlified form

User Will Olbrys
by
7.9k points
2 votes
-16/3v + 16 -3/2v + 12
-41/6v + 28
User Ohmless
by
7.8k points

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