Question

a ten station assembly machine has ideal cycle time of 6 sec. the fraction defect rate at each station 0.005 and defect always jams the affected station. when breakdown occurs it takes 1.2 min on average for the system to be pu back into operation. determine the hourly production rate for the assembly machine.

Answer 1

`T_(P)=(2.6667)(10^(-3))h`

Step-by-step explanation:

Let's write the equation of the production rate for the assembly machine :

`T_(P)=T_(C)+(n).(m).(p).(T_(D))`

Where
`T_(P)` is the production rate for the assembly machine.

Where
`T_(C)` is the ideal cycle time

Where n is the number of stations.

Where m is the number stations that get jam when the defect occurs.

Where p is the defect rate at each station.

And where
`T_(D)` is the average downtime per breakdown

We are looking for the hourly production rate ⇒

`1h=60min\\1min=60s` ⇒

`1h=3600s` ⇒

`6s=((6s)(1h))/((3600s))= (1)/(600)h`

`60min=1h` ⇒

`1.2min=((1.2min)(1h))/((60min))=0.02h`

`T_(P)=(1)/(600)h+(10)(1.0)(0.005)(0.02h)=(1)/(375)h=(2.6667)(10^(-3))h`

m = 1.0 in the equation.