I need to find the standard form of this equation: 4y^2+40y+3x+103=0

asked Sep 25, 2022 157k views

20 votes

I need to find the standard form of this equation:
4y^2+40y+3x+103=0

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0 votes

Answer:

(y+5)^2=-3/4(x+1)

Explanation:

Ldrrp answered Sep 27, 2022

by Ldrrp

4.0k points

8 votes

Hi!

The standard form would be

“4y^2+40y= -3x-103”

Marsx answered Sep 30, 2022

by Marsx

4.7k points

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