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I need to find the standard form of this equation: 4y^2+40y+3x+103=0
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I need to find the standard form of this equation:
4y^2+40y+3x+103=0

User Paceman
by
8.6k points

2 Answers

0 votes

Answer:

(y+5)^2=-3/4(x+1)

Explanation:

User Ldrrp
by
7.9k points
8 votes
Hi!

The standard form would be

“4y^2+40y= -3x-103”


User Marsx
by
8.7k points
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