Question

How many moles are in 17.0 grams of H2O2?​

Answer 1

Answer: 0.500

Explanation:17.0 g H202 x (1 mol H202/34.0 g H202)=0.500 mol H202

Answer 2

Answer: 0.5 moles are present in 17.0 g of
`H_(2)O_(2)` .

Step-by-step explanation:

Number of moles present in a substance is the given mass divided by molar mass of the substance.

As the given mass of
`H_(2)O_(2)` is 17.0 g and its molar mass is 34 g/mol.

Hence, number of moles present in given 17.0 g of
`H_(2)O_(2)` is as follows.

No. of moles =
`(mass)/(molar mass)`

=
`(17.0 g)/(34 g/mol)`

= 0.5 moles

Therefore, 0.5 moles are present in 17.0 g of
`H_(2)O_(2)` .