127k views
14 votes
Polonium-218 undergoes beta decay, converting a neutron into a proton. Then the daughter isotope undergoes another beta decay, again converting a neutron into a proton. Which equation correctly describes this process? Use the periodic table link from the tools bar to answer the question.

Polonium-218 undergoes beta decay, converting a neutron into a proton. Then the daughter-example-1
Polonium-218 undergoes beta decay, converting a neutron into a proton. Then the daughter-example-1
Polonium-218 undergoes beta decay, converting a neutron into a proton. Then the daughter-example-2
Polonium-218 undergoes beta decay, converting a neutron into a proton. Then the daughter-example-3
Polonium-218 undergoes beta decay, converting a neutron into a proton. Then the daughter-example-4
User Octo
by
8.3k points

2 Answers

14 votes

Answer:

A

Step-by-step explanation:

The top dudes answer summed up.

User Ian Hunter
by
7.6k points
6 votes

Answer:
^(218)_(84)Po \rightarrow ^(218)_(85)At + ^(0)_(-1)e is the correct equation for beta decay.

Step-by-step explanation:

When a beta particle, that is,
^(0)_(-1)e is emitted in a radioactive decay then it is known as beta decay.

Therefore, beta decay of Polonium-218 is as follows.


^(218)_(84)Po \rightarrow ^(218)_(85)At + ^(0)_(-1)e

Therefore, we can conclude that
^(218)_(84)Po \rightarrow ^(218)_(85)At + ^(0)_(-1)e is the correct equation for the given beta decay.

User Mark Nunes
by
8.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.