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Polonium-218 undergoes beta decay, converting a neutron into a proton. Then the daughter isotope undergoes another beta decay, again converting a neutron into a proton. Which equation correctly describes this process? Use the periodic table link from the tools bar to answer the question.

Polonium-218 undergoes beta decay, converting a neutron into a proton. Then the daughter-example-1
Polonium-218 undergoes beta decay, converting a neutron into a proton. Then the daughter-example-1
Polonium-218 undergoes beta decay, converting a neutron into a proton. Then the daughter-example-2
Polonium-218 undergoes beta decay, converting a neutron into a proton. Then the daughter-example-3
Polonium-218 undergoes beta decay, converting a neutron into a proton. Then the daughter-example-4
User Octo
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3.7k points

2 Answers

14 votes

Answer:

A

Step-by-step explanation:

The top dudes answer summed up.

User Ian Hunter
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3.2k points
6 votes

Answer:
^(218)_(84)Po \rightarrow ^(218)_(85)At + ^(0)_(-1)e is the correct equation for beta decay.

Step-by-step explanation:

When a beta particle, that is,
^(0)_(-1)e is emitted in a radioactive decay then it is known as beta decay.

Therefore, beta decay of Polonium-218 is as follows.


^(218)_(84)Po \rightarrow ^(218)_(85)At + ^(0)_(-1)e

Therefore, we can conclude that
^(218)_(84)Po \rightarrow ^(218)_(85)At + ^(0)_(-1)e is the correct equation for the given beta decay.

User Mark Nunes
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3.9k points