Step-by-step explanation:
Given that,
Distance covered by the skier, d = 62.5 m
Slope from the horizontal,

Let v is the final speed of the skier. Using the third equation of kinematics as :

Here,
and u = 0



v = 22.75 m/s
The final speed of a skier is 22.75 m/s.
Let t is the time taken. Using the first equation of motion as :


t = 5.49 seconds
Hence, this is the required solution.