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Subtract-3c2 + 12cd – 4d2 from 4c2 + 3cd + 2d?.

Your answer should be a polynomial in standard form.

User Atheer
by
4.5k points

1 Answer

4 votes

Answer:

Subtract
-3c^2 + 12cd - 4d^2 from
4c^2 + 3cd + 2d^2 we get
\mathbf{7c^2-9cd+6d^2}

Explanation:

We need to Subtract
-3c^2 + 12cd - 4d^2 from
4c^2 + 3cd + 2d^2

(Note: Considering 2d^2 instead of 2d as thinking it typo error)

Subtracting from means we have to subtract
4c^2 + 3cd + 2d^2 -(-3c^2 + 12cd - 4d^2)

Subtracting:


4c^2 + 3cd + 2d^2 -(-3c^2 + 12cd - 4d^2)\\=4c^2 + 3cd + 2d^2 +3c^2 - 12cd + 4d^2

Combining like terms (Like terms are those that have same variables like 4c^2 and 3c^2 are like terms, 3cd and -12cd are like terms, 2d^2 and 4d^2 are like terms)


=4c^2+3c^2 + 3cd-12cd + 2d^2+4d^2 \\=7c^2-9cd+6d^2

So, Subtract
-3c^2 + 12cd - 4d^2 from
4c^2 + 3cd + 2d^2 we get
\mathbf{7c^2-9cd+6d^2}

User Shabbir Bata
by
4.4k points