Answer:
The equation of the line is;
y = 4x - 16
Explanation:
Here, we want to find the equation of a line that passes through the point (2,-8) and has a slope of 4
To get this equation, we are going to use the point-slope form
Thus, we have it that;
y-y1 = m(x-x1)
y -(-8) = 4(x-2)
y + 8 = 4x - 8
y = 4x -8-8
y = 4x - 16