Register
Factor completely 6x^3-23x^2+20x
191k views
3 votes
Factor completely 6x^3-23x^2+20x

User Waseem Shah
by
5.0k points

1 Answer

5 votes

Answer:


x[2x - 5][3x - 4]

Explanation:


6x^3 - 23x^2 + 20x \\ x[6x^2 - 23x + 20] \\ \\ [x][6x^2 - 8x] - [15x + 20] \\ \\ [x]2x[3x - 4] \: -5[3x - 4] \\ \\ x[2x - 5][3x - 4]

I am joyous to assist you anytime.

User Arun Bertil
by
5.7k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.6m questions

7.4m answers

Other Questions

Evaluate a + b when a = –16.2 and b = –11.4 A. –27.6 B. –4.8 C. 4.8 D. 27.6
What is the value of x? (-4) - x = 5
Can someone help me with 5??? ASAP?
1/7 + 3/14 equivalent fractions
185g in the ratio 2:3
Link Copied!