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Factor completely 6x^3-23x^2+20x

Factor completely 6x^3-23x^2+20x
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3 votes
Factor completely 6x^3-23x^2+20x

User Waseem Shah
by
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1 Answer

5 votes

Answer:


x[2x - 5][3x - 4]

Explanation:


6x^3 - 23x^2 + 20x \\ x[6x^2 - 23x + 20] \\ \\ [x][6x^2 - 8x] - [15x + 20] \\ \\ [x]2x[3x - 4] \: -5[3x - 4] \\ \\ x[2x - 5][3x - 4]

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User Arun Bertil
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