Question

Consider an ideal monatomic gas of N particles with mass m in thermal equilibrium at a temperature T. The gas is contained in a cube of side L whose top and bottom are parallel to the Earth’s surface, and the gravitational acceleration is a constant g throughout the box. (a) What is the average kinetic energy of an atom of this gas?

Answer 1

`K.E.=(3)/(2)KT`

Step-by-step explanation:

Given that

Number of particle =N

Equilibrium temperature= T

Side of cube = L

Gravitational acceleration =g

The kinetic energy of an atom given as

`K.E.=(3)/(2)KT`

Where

Equilibrium temperature= T

Boltzmann constant =K

K =1.380649×10−23 J/K