Question

A 2000 kg car is driving on a flat road around a turn with a 50 meter radius of curvature. When the road is dry, the car can go around the turn at a maximum speed of 20 m/s without slipping. What is the coefficient of friction between the road and the tires? Is this the coefficient for static or kinetic friction?

Answer 1

μ =0.8

This is the coefficient for kinetic friction

Step-by-step explanation:

Given that

m = 2000 kg

r= 50 m

v= 20 m/s

When a car moves around a circular arc the it experience a radial force F

F= m v²/r

To avoid the slipping friction force must be equal to F

Friction force Fr= μ m g

Fr= F

μ m g= m v²/r

μ = v²/rg

By putting the values

`\mu =(20^2)/(50* 10)` ( take g =10 m/s²)

μ =0.8

This is the coefficient for kinetic friction