Answer: 0.137 m/s
Step-by-step explanation:
from the question we are given the following
mass of train A (Ma) = 150,000 kg
velocity of train A (Va) = 0.3 m/s
mass of train B (Mb) = 95,000 kg
velocity of train B (Vb) = -0.12 m/s
final velocity (V) = ?
mass of both trains = 245,000 kg
- to solve this question we apply the conservation of momentum
MaVa + MbVb = (Ma + Mb) x V
V = (MaVa + MbVb) / (Ma + Mb)
V = ((150,000 x 0.3) + (95,000 x (-0.12))) / (245,000)
V = -33600 / 245,000
V = 0.137 m/s