Question

From a 60 cm rifle pipe the bullet flies out at a speed of 300 meters / second. What iš the avarage speed of bullet in the pipe? How much time was the bullet moving? What is bullet's acceleration?

Thanks​

Answer 1

Step-by-step explanation:

Assuming constant acceleration, the average speed is:

v_avg = ½ (v + v₀)

v_avg = ½ (300 m/s + 0 m/s)

v_avg = 150 m/s

The distance equals the average speed times the time:

Δx = v_avg t

0.60 m = 150 m/s × t

t = 0.004 s

Acceleration is the change in velocity over time:

a = (v − v₀) / t

a = (300 m/s − 0 m/s) / 0.004 s

a = 75,000 m/s²