Question

Iron-59 is used in medicine to diagnose blood circulation disorders. The half life of iron-59 is 44.5 days. How much of a 2.000 mg sample will remain after 133.5 days? Show your work

Answer 1

0.258 mg of iron remains.

Step-by-step explanation:

To solve this problem we can use the formula

M₂ = M₀ *
`0.5^{(t)/(44.5) }`

Where M₂ is the mass remaining, M₀ is the initial mass, and t is time in days.

Using the data given by the problem:

M₂ = 2.000 mg *
`0.5^{(133.5)/(44.5) }`

M₂ = 0.258 mg