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An astronaut and his gear are at rest with respect to his shuttlecraft . The astronaut and the shuttlecraft are initially separated by a distance of m. If the astronaut moves farther away from the shuttlecraft to a distance of m, what is the change in gravitational potential energy for the astronaut–shuttlecraft system?

User Imi Borbas
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Answer:


\Delta F = (Gm_Am_S)[-(1)/(r_2)+(1)/(r_1)]

Step-by-step explanation:

We need the Gravitational Potential Energy equation to give solution to this problem.

This equation is,


F=(-Gm_1m_2)/(r)

Where r is the distance between the corps.

The rate from this gravitational potential energy is given by,


\Delta F = (-Gm_Am_S)/(r_2) - ((Gm_Am_S)/(r_1))


\Delta F = (Gm_Am_S)[-(1)/(r_2)+(1)/(r_1)]

You need only replace the values to find the Energy.

User David Alsbright
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