Answer:
7.92 m/s
Step-by-step explanation:
= Mass of raindrop =
![45m_2](https://img.qammunity.org/2020/formulas/physics/high-school/w8p822edyalcuhomz85qi9f8z2p4yxqxwu.png)
= Mass of mosquito
= Initial Velocity of raindrop = 8.1 m/s
= Initial Velocity of mosquito = 0 m/s
= Velocity of center of mass
For elastic collision
![m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=(m_1u_1 + m_2u_2)/(m_1 + m_2)\\\Rightarrow v=(45m_2* 8.1 + m_2* 0)/(45m_2 + m_2)\\\Rightarrow v=(364.5m_2)/(46m_2)\\\Rightarrow v=7.92\ m/s](https://img.qammunity.org/2020/formulas/physics/high-school/uiq4pxdzayqarpicvtxsiswf9eehj4zyvf.png)
Hence, the velocity of the attached mosquito, falling immediately afterward is 7.92 m/s