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A hot-air balloon descends from a height of 2000 feet for 40 seconds. The function models the height of the hot-air balloon during this descent, where t is the amount of time since the descent began. What is the practical domain of the function in this situation? What is the practical range of the function in this situation?

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Answer:

The domain is all real values greater than or equal to 0 seconds and less than or equal to 40 seconds

The range is all real values greater than or equal to 0 feet and less than or equal to 2,000 feet

Explanation:

Let

t ----> is the amount of time since the descent began

f(t) ---> is the height of a hot-air balloon descends

we know that

The linear equation in slope intercept form is equal to


y=mx+b

where

m is the unit rate or slope of the linear equation

b is the y-intercept or initial value

In this problem we have that

The slope or unit rate is equal to


m=-(2,000)/(40)=-50\ feet\ per\ second ---> is negative because is a decreasing function

The y-intercept or initial value is equal to


b=2,000\ ft

substitute


f(t)=-50t+2,000

The domain is the interval -----> [0,40]


0\leq t\leq 40

All real values greater than or equal to 0 seconds and less than or equal to 40 seconds

The range is the interval ----> [0,2,000]


0\leq f(t)\leq 2,000

All real values greater than or equal to 0 feet and less than or equal to 2,000 feet

User Jimmy Gong
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