Question

A company produces two different sizes of soup cans. The volume of the cans varies jointly with the square of the can's radius and the height. The smaller can has a height of 5 inches, a squared radius of 4 inches, and a volume of about 62.8 cubic inches. What is the volume of the taller can, which has a height of 9 inches and a squared radius of 4 inches? Round to the nearest tenth, as needed.

A. V=113.0
B. V=36.0
C. V=3.1
D. 91.3

Answer 1

A=113.0

Hope it helps guys!! :)

Answer 2

• A. V= 113 in³

Explanation:

Volume formula will be:

• V = kr²h,

where V - volume, k - coefficient of proportion, r² - squared radius, h - height

Substitute the known values to find the unknown:

• 62.8 = k*4*5
• 62.8 = 20k
• k = 62.8/20
• k = 3.14

Now find the volume of the taller can:

• V = kr²h
• V = 3.14*4*9 = 113.04 ≈ 113 in³

Correct option is A