Answer:
P=900W
Step-by-step explanation:
We need to define a variable, where the system can be used without tripping the circuit.
So we define,

Making the substitution for
and
, we can find
,

We know as well that the power required to operate is 1500W(P_{B}, so
P=P_{A}-P_{B}
Making the substitution for the values we have,

So we found the power setting at which the circuit breaker trips.